Question #253426

In the laboratory, you attach a 300g mass to a spring of negligible mass and let it start to oscillate. The elapsed time from when the mass first moves through the equilibrium position to the second time it moves through that point is 2s. Find the force constant of the spring.


Expert's answer

Given:

m=0.3kgm=0.3\:\rm kg

τ=2s\tau=2\:\rm s

The period of oscillation

T=2τ=22s=4sT=2\tau=2*2\:\rm s=4\:\rm s


Also

T=2πmkT=2\pi\sqrt{\frac{m}{k}}

Hense, the force constant of the spring

k=4π2mT2=43.1420.342=0.74N/mk=\frac{4\pi^2m}{T^2}=\frac{4*3.14^2*0.3}{4^2}=0.74\:\rm N/m
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