Answer to Question #253096 in Physics for Inday

Question

What is the escape velocity at the surface of the sun?

Answer 1

The escape velocity is

$$v=\sqrt\frac{2GM}{R}=\sqrt\frac{2(6.673·10^{-11})(1.989 · 10^{30})}{6.957·10^8}=618\text{ km/s}.$$