Answer to Question #253092 in Physics for Inday

Question

At the surface of Earth, the escape velocity of a 2 kg projectile is about 11 km/s when air resistance is ignored.

For a 4 kg projectile, the corresponding escape velocity is

Answer 1

The escape velocity can be found as follows:

$$v_{escape}=\sqrt{\dfrac{2GM}{r}},$$

here, $G$ is universal gravitational constant, $M$ is the mass of Earth and $r$ is the radius of Earth.

As we can see from the formula, the escape velocity does not depend on the mass of the projectile. Therefore, for a 4 kg projectile, the corresponding escape velocity will be 11 km/s.