Question

If a 50 lb force is applied at the end of a wrench that is 1 ft long, how much torque
is developed?

Answer 1

Given:

$F=50\:\rm lb$

$d=1\:\rm ft$

The torque

$$\tau=Fd\\=\rm (50\: lb)*(1\:ft)=50\: lb\cdot ft=68\: N\cdot m$$