Question #252878
If a force of 100 kg displaces 12 m in 1 min, how much work has been done?
1
Expert's answer
2021-10-18T11:39:36-0400
W=Fd=100 kgf⋅9.8 N1 kgf⋅12 m=11760 J.W=Fd=100\ kgf\cdot\dfrac{9.8\ N}{1\ kgf}\cdot12\ m=11760\ J.

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