Question

a piston that is part inches of a hydraulic system has a surface area of 36.98 square inches. the hydraulic fluid pushes on the poston with a pressure of 241.02 psi. What force in KN pushes on the piston in the same system?

Answer 1

The force is F=pA. Convert the area to square centimeters:

$$A=36.98·0.0006=0.0222\text{ m}^2.$$

The pressure is

$$p=241.02·6894.76=1661774.4\text{ Pa}.\\\space\\ F=pA=36.891\text{ kN}.$$