Question

A ball is kicked with an initial velocity of 20.0m/s at an angle 30 ° above the ground. What are the horizontal and vertical components of its velocity after 1.0s?

Answer 1

The projections of velocity of a ball are given by

$$v_x(t)=v_0\cos\theta\\ v_y(t)=v_0\sin\theta-gt$$

Hence, after one second

$$v_x(1.0)=20.0\cos30^{\circ}=17.3\:{\rm m/s}\\ v_y(1.0)=20.0\sin30^{\circ}-9.8*1.0=0.2\:{\rm m/s}$$