Question #251349



7.     

An engineer is designing the runway for

an airport. Of the planes that will use the airport, the lowest acceleration

rate is likely to be 2.50 m/s^2. The takeoff speed for this plane

will be 70.00 m/s. Assuming this minimum acceleration, what is the minimum

allowed length for the runway?

8.     

It was once recorded that a Jaguar left

skid marks that were 270.00 m in length. Assuming that the Jaguar skidded to a

stop with a constant acceleration of -3.60 m/s^2, determine the speed

of the Jaguar before it began to skid.

9.     

A speedboat increases its speed

uniformly from 20 m/s to 30 m/s in a distance of 300m. Find the time it take

the boat to travel the 300 m distance.


1
Expert's answer
2021-10-14T18:38:59-0400

7. Using one of the kinematic formulas (see https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematic-formulas/a/what-are-the-kinematic-formulas), find the distance:


d=v2v022ad = \dfrac{v^2-v_0^2}{2a}

where v=70.00m/sv = 70.00m/s is the final speed, v0=0v_0 = 0 is the initial speed (assuming start from rest), and a=2.50m/s2a = 2.50m/s^2 is the acceleration. Thus, obtain:


d=7020222.5=980md = \dfrac{70^2-0^2}{2\cdot 2.5} =980m

8. Using the same equation, let's express now v0v_0 and substitute v=0v=0 (final speed zero, came to rest), d=270.00md = 270.00m and a=3.60m/s2a = -3.60m/s^2:


v0=2adv0=2270m(3.6m/s2)44.1m/sv_0 = \sqrt{-2ad}\\ v_0 = \sqrt{-2\cdot 270m\cdot (-3.6m/s^2)} \approx 44.1m/s



9. Using the different kinematic equation, obtain:


d=v+v02td = \dfrac{v+v_0}{2}t

where d=300m,v=30m/s,v0=20m/sd=300m,v = 30m/s,v_0=20m/s and tt is the required time. Expressing time, find:


t=2dv+v0=2300m30m/s+20m/s=12st = \dfrac{2d}{v + v_0} = \dfrac{2\cdot 300m}{30m/s + 20m/s} = 12s

Answer. 7) 980m, 8) 44.1m/s, 9) 12s.


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