Question

a soccer player kicks a ball at an angle of 43 degrees with a speed of 10 m per second how far from the initial position will the ball land

Answer 1

Using the formula for range from here https://courses.lumenlearning.com/boundless-physics/chapter/projectile-motion/ , obtain:

$$R = \dfrac{u^2\sin2\theta}{g}$$

where $u = 10m/s$ is the initial speed, $\theta=43\degree$ is the launch angle, $g = 9.8m/s^2$ is the gravitational acceleration. Thus, have:

$$R = \dfrac{(10m/s)^2\cdot \sin(2\cdot 43\degree)}{9.8m/s^2} \approx 10m$$

Answer. 10m.