Question #251127

An axe that weighs 8.0 kg is used to strikes the log with a force of 400 N that comes

to rest in 0.04 seconds. What is the magnitude of the impulse? How fast is the axe approach the log?


1
Expert's answer
2021-10-14T11:32:08-0400

The magnitude of impulse is


I=Ft=4000.04=16 kg m/s.I=Ft=400·0.04=16\text{ kg m/s}.

The speed is


v=at=Fmt=40080.04=2 m/s.v=at=\frac Fmt=\frac{400}8·0.04=2\text{ m/s}.


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