Answer to Question #250575 in Physics for Farama

Question

A spring of natural length 3cm is extended by 100cm by a force of 9n what will be it's length when applied force is 10n

Answer 1

From the data of the first experiment, find the spring constant:

$$k=\frac F{\Delta x}=9\text{ N/m}.$$

Now, determine the elongation under the force of 10 N:

$$\Delta x_2=\frac {F_2}k=111\text{ cm}.$$

The total length will be

$$L=x_0+\Delta x_2=114\text{ cm}.$$