Question

The moment of inertia of a dancer is 7. 0 𝑘𝑔 𝑚 when she performs 48 rotations per 2 minute with both arms outstretched. The moment of inertia reduces to 2. 2 𝑘𝑔 𝑚 when 2 she wraps her arms around her body. Calculate the new number of rotations per se

Answer 1

$I_1\omega_1=I_2\omega_2\to \omega_2=I_1\omega_1/I_2=7\cdot2.513/2.2\approx8\ (rad/s)=1.27\ (rev/s)$ . Answer