The moment of inertia of a dancer is 7. 0 ππ π when she performs 48 rotations per 2 minute with both arms outstretched. The moment of inertia reduces to 2. 2 ππ π when 2 she wraps her arms around her body. Calculate the new number of rotations per se
"I_1\\omega_1=I_2\\omega_2\\to \\omega_2=I_1\\omega_1\/I_2=7\\cdot2.513\/2.2\\approx8\\ (rad\/s)=1.27\\ (rev\/s)" . Answer
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