Question #250433

A ball is launched horizontally from the top of a 12 m tall vertical cliff. The ball has an initial

horizontal speed of 8.4 m/s.


1
Expert's answer
2021-10-12T12:35:30-0400

A ball is launched horizontally from the top of a 12 m tall vertical cliff. The ball has an initial

horizontal speed of 8.4 m/s. What is the flight time of the ball?


h=gt2/2t=2h/g=212/9.8=1.56 (s)h=gt^2/2\to t=\sqrt{2h/g}=\sqrt{2\cdot12/9.8}=1.56\ (s)


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