Question #250261

If a force of 25 N stretches a spring 0.20 m, what is the spring constant? 


1
Expert's answer
2021-10-14T11:31:24-0400

F=kx→k=F/x=25/0.2=125 (N/m)F=kx\to k=F/x=25/0.2=125\ (N/m) . Answer


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