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Question #249924
.A shelter Island ferry boat moves with a cosntant velocity vox =8 m/sfor 60 sec.It
then shuts off its engines and coasts.Its coasting velocity is given by vx = vox t^2(1 /t^2)
,
where t1= 60 s.What is the displacement of the boat for the interval 0<t<Ã ¢ ?
Expert's answer
Displacement during 60 s:
Δ
x
1
=
v
0
x
6
0
2
/
6
0
2
=
8
m
.
\Delta x_1=v_{0x}60^2/60^2=8\text{ m}.
Δ
x
1
=
v
0
x
6
0
2
/6
0
2
=
8
m
.
Displacement during 0<t<∞:
Δ
x
2
=
∫
T
∞
v
x
d
t
=
=
v
0
x
T
2
∫
T
∞
1
t
2
d
t
=
480
m
.
Δ
x
=
Δ
x
1
+
Δ
x
2
=
488
m
.
\Delta x_2=\int^\infty_Tv_x\text dt=\\\space\\ =v_{0x}T^2\int^\infty_T\frac1{t^2}\text dt=480\text{ m}.\\\space\\ \Delta x=\Delta x_1+\Delta x_2=488\text{ m}.
Δ
x
2
=
∫
T
∞
v
x
d
t
=
=
v
0
x
T
2
∫
T
∞
t
2
1
d
t
=
480
m
.
Δ
x
=
Δ
x
1
+
Δ
x
2
=
488
m
.
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on Dec 2023
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