Question

after catching the final out, an outfielder throws the baseball straight up in the air with an initial speed of 35 m/s. How long does it take to reach its highest point?

Answer 1

$$v_y=v_{0y}-gt,$$ $$0=v_{0y}-gt,$$ $$t=\dfrac{v_{0y}}{g}=\dfrac{35\ \dfrac{m}{s}}{9.8\ \dfrac{m}{s^2}}=3.6\ s.$$