Answer to Question #248493 in Physics for Rod

Question #248493

Find the range of an arrow that leaves the box at 50 m/s at ang angle of 50o above the horizontal?



1
Expert's answer
2021-10-08T09:21:59-0400

Given:

v0=50m/sv_0=50\:\rm m/s

θ=50\theta=50^{\circ}


The range is given by

R=v02sin2θg=502sin1009.8=251mR=\frac{v_0^2\sin2\theta}{g}=\frac{50^2\sin100^{\circ}}{9.8}=251\:\rm m


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