Question #247838

A car slows from 22 m/s to 3.0 m/s with a constant acceleration of -2.1 m/s2.  How long does it require in the unit of seconds?


1
Expert's answer
2021-10-07T08:49:37-0400

By definition, the acceleration is given as follows:


a=vfvita = \dfrac{v_f-v_i}{t}

where vf=3m/s,vi=22m/sv_f = 3m/s,v_i = 22m/s are final and initial speeds respectively, and tt is the time. Expressing the time and substituting a=2.1m/s2a = -2.1m/s^2, obtain:


t=vfvia=3m/s22m/s2.1m/s29.0st = \dfrac{v_f-v_i}{a} = \dfrac{3m/s - 22m/s}{-2.1m/s^2} \approx 9.0s

Answer. 9.0 s.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS