Question #246756
A girl kicked the ball with initial velocity of 20m/s at an angle of 40degrees with thehorizontal
Calculate the maximum height reached
Calculate the time of flight
Calculate zthe horizontal displacement of the projectile
1
Expert's answer
2021-10-05T10:06:13-0400

Height:


H=v2sin2θ2g=8.43 m.H=\frac{v^2\sin^2\theta}{2g}=8.43\text{ m}.

Time:


T=2vsinθg=2.6 s.T=\frac{2v\sin\theta}{g}=2.6\text{ s}.

Displacement:


D=v2sin(2θ)g=40.2 m.D=\frac{v^2\sin(2\theta)}{g}=40.2\text{ m}.


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