Answer to Question #246756 in Physics for Joy

Question

A girl kicked the ball with initial velocity of 20m/s at an angle of 40degrees with thehorizontal
Calculate the maximum height reached
Calculate the time of flight
Calculate zthe horizontal displacement of the projectile

Answer 1

Height:

$$H=\frac{v^2\sin^2\theta}{2g}=8.43\text{ m}.$$

Time:

$$T=\frac{2v\sin\theta}{g}=2.6\text{ s}.$$

Displacement:

$$D=\frac{v^2\sin(2\theta)}{g}=40.2\text{ m}.$$