According to Newton's second law for the block:
ma=−μmgcosθ+mgsinθ−T. By Newton's second law for rotational motion:
Iα=Tr. Write the equation that relates the angular and tangential acceleration, substitute, and solve for tension:
a=αr: Ira=[mg(sinθ−μcosθ)−ma]r, Ira=mgr(sinθ−μcosθ)−mar, a(rI−mr)=mgr(sinθ−μcosθ), a=I−mr2mgr2(sinθ−μcosθ)=0.48 m/s2. T=mg(sinθ−μcosθ)−ma=3.85 N.
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