Question #246113

A box weighing 15 ๐‘™๐‘ is pulled by a force of 10 ๐‘™๐‘ along a plane inclined 30o with the horizontal, the force being parallel to the plane. Starting from rest, how far will the box travel after 5 ๐‘ ๐‘’๐‘? 


1
Expert's answer
2021-10-07T09:04:33-0400

Determine the acceleration of the box:


a=Fcosโก30ยฐm=(10โ‹…32)cosโก30ยฐ15=18.5 lb/s2.a=\frac{F\cos30ยฐ}m=\frac{(10ยท32)\cos30ยฐ}{15}=18.5\text{ lb/s}^2.


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