The brakes of a 1000 ππ automobile can exert a retarding force of 3,000π. Find the distance the car will move before stropping if it is traveling at the rate of 24 π/π when the brakes are applied (96 π).Β
"a=F\/m=3000\/1000=3\\ (m\/s^2)"
"s=v^2\/(2a)=24^2\/(2\\cdot3)=96\\ (m)" . Answer
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