Question

The brakes of a 1000 𝑘𝑔 automobile can exert a retarding force of 3,000𝑁. Find the distance the car will move before stropping if it is traveling at the rate of 24 𝑚/𝑠 when the brakes are applied (96 𝑚). 

Answer 1

$a=F/m=3000/1000=3\ (m/s^2)$

$s=v^2/(2a)=24^2/(2\cdot3)=96\ (m)$ . Answer