Question #245963

The ball is initially at 2ȋ + 0ĵ + 3k̂ then it moved to 4ȋ + 0ĵ + 5k̂ , its total displacement is 6ȋ + 0ĵ + 8k̂ .


1
Expert's answer
2021-10-03T13:23:05-0400

If the body is initially at 2ȋ + 0ĵ + 3k̂ and then it moved to 4ȋ + 0ĵ + 5k̂, the total displacement is


d=(rx2rx1)2+(ry2ry1)2+(rz2rz1)2==(42)2+(00)2+(53)2=2.83.d=\sqrt{(r_{x2}-r_{x1})^2+(r_{y2}-r_{y1})^2+(r_{z2}-r_{z1})^2}=\\ =\sqrt{(4-2)^2+(0-0)^2+(5-3)^2}=2.83.


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