Answer to Question #245927 in Physics for Sumanget

Question

If the system rotates perpendicular to the page at A and has a speed of 500rpm. Find a) rotational kinetic energy (KEr) b) angular momentum (L)

Answer 1

Convert 500 rpm to rad/s:

$\omega=2\pi n=2\pi\frac{500}{60}=53.4\text{ rad/s}.$

Rotational kinetic energy:

$E=\frac12 I\omega^2=1426I\text{ J}.$

The angular momentum is

$L=I\omega=53.4I\text{ km}·\text{m}^2/\text{s}.$

I is the moment of inertia of the system.