Question #245726

Using the impulse momentum theorem,

The question:

Suppose a player hits a ball of mass 0.145 kg with a racket, and that the velocity of the ball before hitting the racket is -38 m/s. Assuming the positive direction towards the pitcher, the initial momentum of the baseball is: pi=(0.145kg) (-38m/s) =--5.5kg.m/s .) What is the momentum of the ball after the collision? Apply the theory of impulse and momentum to find the final momentum


Expert's answer

The momentum of the ball after the collision is


pf=pi=5.5 kg m/s.p_f=-p_i=5.5\text{ kg m/s}.


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