a) The torque the wind creates is
h=d+l - height between the base and the basket.
The torque that creates the base is
r - the half of length of the base, W - weight of the base.
As the basketball set inclines just a little bit, the weight of the post arrangement starts creating its torque that helps the wind:
As we see, the set topples over when the wind creates enough torque to rotate the base with the post for angle θ at which the torques of the post and base become equal:
"W_br\\cos\\theta=W_al\\sin\\theta,\\\\\\space\\\\\n\\theta=\\arctan\\frac{W_br}{W_al}=75\u00b0."
Until this angle, the magnitude of wind force required to topple over the set is decreasing.
So, the initial force of wind it
"\\tau_w=F_wh=\\tau_b=W_br\\cos0\u00b0,\\\\\\space\\\\\nF_w=\\frac{W_br}{h}=\\frac{W_br}{d+l}=86.2\\text{ N}."
b) Since the density of sand is greater than density of water, Wb will increase and, according to the last equation, more force will be required.
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