The general equation for the transverse wave is given as follows:
y(x,t)=Asin(λ2πx−2πft) where A is the amplitude, λ is the wavelength, f is the frequency of the wave, v=λf is its speed and T=1/f is its period.
Comparing this expression with the given one, find:
A=0.2mλ2π=6.28⇒λ≈1m2πf=1.57⇒f≈0.25HzT=1/f≈4sv=λf=0.25m/s Answer. a) 0.2m, b) 1m, c) 4s, d) 0.25 m/s.
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