Question

Determine the horizontal and vertical components of a bus if it is moving at 80km/h going 22° south of west

Answer 1

Let $\theta =22\degree$ and $\mathbf{v}$ be the vector of velocity with magnitude $v = 80km/h$.

Then its horizontal component is:

$$v_x = -v\cos\theta = -80\cdot \cos22\degree \approx -74.2m/s$$

Vertical component:

$$v_x = -v\sin\theta = -80\cdot \sin22\degree \approx -30.0m/s$$

Answer. Horiaontal: -74.2 m/s, vertical: -30.0 m/s.