Question

A gymnasium is 16 m high. By what percent is the air pressure at the floor greater than the air pressure at the ceiling? Assume that pressure at the bottom is 1 atm and the density of air stays constant. The density of air is 1.29 kg/m³. 

Answer 1

$$E=\frac{\rho gh}{P}\\E=\frac{(1.29)(9.8)(16)}{101325}=0.2\%$$