(a) The time is
"t=\\frac{\\omega_o}{\\alpha}=\\frac{5.5}{4.15}=1.32\\text{ s}." (b) During the 7 s:
"n_1=\\frac{\\phi_1}{2\\pi}=\\frac{\\omega_dt_1}{4\\pi}=\\frac{6\u00b77}{4\\pi}=3."
During the 13 s:
"n_2=\\frac{\\phi_2}{2\\pi}=\\frac{\\omega_dt_2}{4\\pi}=\\frac{6\u00b713}{4\\pi}=6."
The total number of revolutions is
"n=n_1+n_2=9."
Comments
Dear Nazirah, this means 6 \times 7 and 6 \times 13
How did you get 6.7 and 6.13?
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