Answer to Question #244592 in Physics for Washington

Question

Derive the dimension of power

Answer 1

By definition, the power is work per second. Thus, the units of power are:

$$[P] = \dfrac{J}{s}$$

Since $J = kg\cdot m^2/s^2$, have:

$$[P] = \dfrac{kg\cdot m^2}{s^3}$$

The dimension is then:

$$[P] = ML^2T^{-3}$$

Answer. $[P] = ML^2T^{-3}$.