Question

An airplane trip involves three legs, with two stopovers. The first leg is due East for 620 km the second leg is Southeast (45

Answer 1

Although the condition is incomplete, assume the second leg is 45° SE and it is 500 km long. The displacement between the airport of departure and the first stopover is

$$D_E=620+500\cos45°=974\text{ km}.\\ D_S=0+500\sin45°=354\text{ km},\\\space\\ D=\sqrt{D_E^2+D_S^2}=1036\text{ km}.$$