Answer to Question #244254 in Physics for Josh

Question

An airplane trip involves three legs, with two stopovers. The first leg is due East for 620 km the second leg is Southeast (45

Answer 1

Although the condition is incomplete, assume the second leg is 45° SE and it is 500 km long. The displacement between the airport of departure and the first stopover is

$$D_E=620+500\cos45°=974\text{ km}.\\ D_S=0+500\sin45°=354\text{ km},\\\space\\ D=\sqrt{D_E^2+D_S^2}=1036\text{ km}.$$