Question

A 5.0kg ball is projected up along a plane that is inclined 20 degrees with the horizontal. What is its potential emergy when it moved 2.3m up along the plane?​

Answer 1

The potential energy

$$E_p=mgh=mgl\sin\theta\\ =\rm5.0\: kg*9.8\: m/s^2*2.3\: m*\sin20^{\circ}=38.5\: J$$