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Question #244065
Projectile motion: other applications
A boy throws a rock with speed v = 18.3 m/s at an angel of theta = 57.0 over a building. The rock lands on the roof 15.0 m in the x direction from the boy. How long was the rock in the air? How much taller, height h, is the building than the boy? Ignore air resistance.
Expert's answer
The time to pass the 25 m along the horizontal is
t
=
R
v
cos
θ
=
1.5
s
.
t=\frac{R}{v\cos\theta}=1.5\text{ s}.
t
=
v
cos
θ
R
=
1.5
s
.
The height of the point, thus, is
h
=
v
y
f
2
−
v
y
0
2
2
g
=
(
v
sin
θ
−
g
t
)
2
−
(
v
sin
θ
)
2
2
g
=
12
m
.
h=\frac{v_{yf}^2-v_{y0}^2}{2g}=\frac{(v\sin\theta-gt)^2-(v\sin\theta)^2}{2g}=12\text{ m}.
h
=
2
g
v
y
f
2
−
v
y
0
2
=
2
g
(
v
sin
θ
−
g
t
)
2
−
(
v
sin
θ
)
2
=
12
m
.
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