Question #243395

Point charges q1 = 50 µC and q2 = −75 µC are placed 1 m apart. Determine the

magnitude and direction of the force on a third charge q3 = 20 µC placed midway

between q1 and q2


1
Expert's answer
2021-09-28T11:11:47-0400

The force from q1:


F13=kq1q3r2, F23=kq2q3r2, F3=F23+F13=kr2(q2q3+q1q3)= =91090.52((75μ)(20μ)+(50μ)(20μ))= =18 N toward q1 or 18 N toward q2.F_{13}=k\frac{q_1q_3}{r^2},\\\space\\ F_{23}=k\frac{q_2q_3}{r^2},\\\space\\ F_3=F_{23}+F_{13}=\frac k{r^2}(q_2q_3+q_1q_3)=\\\space\\ =\frac {9·10^9}{0.5^2}((-75\mu)(20\mu)+(50\mu)(20\mu))=\\\space\\ =-18\text{ N toward q}_1\text{ or 18 N toward q}_2.

The third charge will be pulled toward q2 (pushed from q1 toward q2).


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