Question #243145

Determine the impulse required to stop a 0.145 kg baseball moving at 35.7 m/s.


1
Expert's answer
2021-09-30T10:20:50-0400

The impulse is


J=mvfmvi=0.14500.14535.7==5.18 kmm/s.|J|=|mv_f-mv_i|=|0.145·0-0.145·35.7|=\\=5.18\text{}\text{ km}·\text{m/s}.



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