First, find the deviation of each value from the average value μ:
μ=52.50+2.55+2.52+2.51+2.56=2.53 MPa. Find the deviations:
δ1=∣μ−x1∣=2.53−2.50=0.03 MPa,δ2=∣μ−x2∣=∣2.53−2.55∣=0.02 MPa,δ3=0.01 MPa,δ4=0.02 MPa,δ5=0.03 MPa.
The absolute uncertainty is
δ=n∑i=1nδi=50.03+0.02+0.01+0.02+0.03=0.02 MPa.
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