Question #243001

Determine the impulse required to stop a 0.145 kg baseball moving at 35/7 m/s.


1
Expert's answer
2021-09-27T10:11:38-0400

The impulse is


J=∣pf−pi∣=∣mvf−mvi∣==∣0.145⋅0−0.145⋅35/7∣=0.725 kg⋅m/s.J=|p_f-p_i|=|mv_f-mv_i|=\\ =|0.145·0-0.145·35/7|=0.725\text{ kg}·\text{m/s}.


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