Question

8. A 0.0450-kg golf ball initially at rest is given a speed of 25.0 m/s when it is struck by a club. If the club and ball are in contact for 2.00 ms, what average force acts on the ball? Is the effect of the ball’s weight during the time of contact significant? Why or why not? 

Answer 1

Given:

$m=0.045\:\rm kg$

$\Delta v=25.0\:\rm m/s$

$\Delta t=2.00\:\rm ms=2.00*10^{-3}\: s$

The average force acts on the ball

$$F=m\frac{\Delta v}{\Delta t}$$

$$F=0.045\:\rm kg*\frac{25.0\:\rm m/s}{2.00*10^{-3}\: s}=563\: N$$

The weight of the ball

$$W=mg=0.045\:\rm kg*9.8\:\rm m/s^2=0.44\: N\ll F$$

Weight is not significant.