Question #242017

An empty swimming pool with a square floor dimension has a volume of 3y2 m3. Given the weight of air in the swimming pool is about 500 N and the air density is 1.29 kg/m3.

(a) Find the length of the swimming pool’s floor, y.

(b) Determine the force exerted by air on the floor of the swimming pool.


Expert's answer

Weight of the air and the side:


W=mg=ρVg=ρAhg=ρa2hg, a=W/(ρhg)=3.63 m.W=mg=\rho Vg=\rho Ahg=\rho a^2hg,\\\space\\ a=\sqrt{W/(\rho hg)}=3.63\text{ m}.

The force:


F=pa2=ρgha2=500 N.F=pa^2=\rho gha^2=500\text{ N}.


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