Determine the distance travelled by the vehicle between time t=120s and time t=160s
a=Δv/Δt=(20−30)/(160−120)=−0.25 (m/s2)a=\Delta v/\Delta t=(20-30)/(160-120)=-0.25\ (m/s^2)a=Δv/Δt=(20−30)/(160−120)=−0.25 (m/s2)
s=(v2−v02)/(2a)=(202−302)/(2⋅(−0.25))=1000 (m)s=(v^2-v_0^2)/(2a)=(20^2-30^2)/(2\cdot(-0.25))=1000\ (m)s=(v2−v02)/(2a)=(202−302)/(2⋅(−0.25))=1000 (m) . Answer
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