Answer to Question #241415 in Physics for Sri

Question

The Fermi enrgy of copper is 7 eV. (use h = 6.6 ×10−34JHz−1 , 1eV = 1.602×10−19J, me=9.1×10−31 kg )The de Broglie wavelength of the electron is ________

3.84×10−10 m


3.64×10−10 m


4.64×10−10 m


4.84×10−10 m

Answer 1

The following equation relates Fermi energy to de Broglie wavelength:

$$\lambda=\frac{h}{\sqrt{2mE_F}}=4.64·10^{-10}\text{ m}.$$