Question

a vehicle leaves a point a with a speed of 5m.s and travels 20 m to reach 18m.s . Found the acceleration

Answer 1

$$v^2=v_0^2+2ad,$$ $$a=\dfrac{v^2-v_0^2}{2d}=\dfrac{(18\ \dfrac{m}{s})^2-(5\ \dfrac{m}{s})^2}{2\cdot20\ m}=7.47\ \dfrac{m}{s^2}.$$