A car starts from rest and acquires a velocity of 70 km/h in 20 minutes. Find a) the acceleration; b) the distance traveled in 20 minutes, and c) the distance traveled in the next 20 minutes.
70 km/h=19.4 m/s70\ km/h=19.4\ m/s70 km/h=19.4 m/s
20 min=1200 s20\ min=1200\ s20 min=1200 s
a) v=at→a=v/t=19.4/1200=0.016 (m/s2)v=at\to a=v/t=19.4/1200=0.016\ (m/s^2)v=at→a=v/t=19.4/1200=0.016 (m/s2)
b) s=at2/2=0.016⋅12002/2=11640 (m)s=at^2/2=0.016\cdot1200^2/2=11640\ (m)s=at2/2=0.016⋅12002/2=11640 (m)
c) s1=v0t+at2/2=19.4⋅1200+0.016⋅12002/2=34800 (m)s_1=v_0t+at^2/2=19.4\cdot1200+0.016\cdot1200^2/2=34800\ (m)s1=v0t+at2/2=19.4⋅1200+0.016⋅12002/2=34800 (m)
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