5. An object traveling with a speed of 10 m/s slides on a horizontal floor. How far will it travel before coming to rest if the coefficient of friction is 0.30?
Ff=ma→μN=ma→μmg=ma→a=μg=0.3⋅9.81=2.943 (m/s2)F_f=ma\to \mu N=ma\to\mu mg=ma\to a=\mu g=0.3\cdot9.81=2.943\ (m/s^2)Ff=ma→μN=ma→μmg=ma→a=μg=0.3⋅9.81=2.943 (m/s2)
s=v22a=1022⋅2.943≈17 (m)s=\frac{v^2}{2a}=\frac{10^2}{2\cdot2.943}\approx17 \ (m)s=2av2=2⋅2.943102≈17 (m) . Answer
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