Answer to Question #239062 in Physics for Reena Biswas

Question

The Fermi enrgy of copper is 7 eV. (use h = 6.6 ×10−34JHz−1 , 1eV = 1.602×10−19J, me=9.1×10−31 kg ).
The Fermi velocity is ?

Answer 1

The Fermi velocity is given as follows (see https://en.wikipedia.org/wiki/Fermi_energy):

$$v_F = \sqrt{\dfrac{2E_F}{m_e}}$$

where $E_F = 7eV = 7\cdot 1.602×10^{−19}J \approx 1.121\times 10^{-18}J$ is the Fermi energy, and $m_e = 9.1×10^{−31} kg$ is the mass of electron. Thus, obtain:

$$v_F = \sqrt{\dfrac{2\cdot 1.121\times 10^{-18}}{9.1\times 10^{-31}}} \approx 4.96\times 10^6m/s$$

Answer. $4.96\times 10^6m/s$ .