Answer to Question #239061 in Physics for Reena Biswas

Question #239061

The Fermi enrgy of copper is 7 eV. (use h = 6.6 ×10−34JHz−1 , 1eV = 1.602×10−19J, me=9.1×10−31 kg ).
The de Broglie wavelength of the electron is?

Expert's answer

"\\lambda=\\frac{hc}{E}\\\\\\lambda=\\frac{1239.84}{7}=177\\ nm"

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