Question #239060
The Fermi enrgy of copper is 7 eV. (use h = 6.6 ×10−34JHz−1 , 1eV = 1.602×10−19J, me=9.1×10−31 kg ).
The Fermi momentum of electron in copper is?
1
Expert's answer
2021-09-21T11:50:33-0400

The electron has a kinetic energy equal to the Fermi energy for copper


K=7 (eV)=11.2141019 (J)K=7\ (eV)=11.214\cdot10^{-19}\ (J) . So,


p=2mK=29.1103111.2141019=1.431024 (kgm/s)=p=\sqrt{2mK}=\sqrt{2\cdot9.1\cdot10^{-31}\cdot11.214\cdot10^{-19}}=1.43\cdot10^{-24}\ (kg\cdot m/s)=


=2.678103 (eV/c)=2.678\cdot10^3\ (eV/c) .



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