A block weighing 48n is pull along a horizontal surface with a rope.The applied force due to the rope is 40n as 37degree to the horizontal.if the block accelerate as 5m/s how large a frictional force must be retarding it motion
"F_x=40\\cdot\\cos37\u00b0\\approx32\\ (N)" ;
"m=48\/9.81=4.1\\ (kg)"
"F=ma\\to -F_f+F_x=ma\\to F_f=F_x-ma=32-4.1\\cdot5=11.5\\ (N)" . Answer
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