Question

A motorcycle was observed to have a velocity of 10m/s when it passed by town A,
and a velocity of 25m/s when it reached town B. If the two towns are 10km apart,
what was the motorcycle’s acceleration, as well as its travel time?

Answer 1

The distance traveled by motorcycle 

$$d=\frac{v_2^2-v_1^2}{2a}$$

The acceleration

$$a=\frac{v_2^2-v_1^2}{2d}$$

$$a=\rm\frac{(25\: m/s)^2-(10\: m/s)^2}{2*10000\: m}=0.026 \: m/s^2$$